2.4525t^2-6t=0

Solution for 2.4525t^2-6t=0 equation:

2.4525t^2-6t=0

a = 2.4525; b = -6; c = 0;
Δ = b2-4ac
Δ = -62-4·2.4525·0
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{36}=6$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-6}{2*2.4525}=\frac{0}{4.905}
=0
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+6}{2*2.4525}=\frac{12}{4.905}
=2+1/2.2397260273973
$